mass of oil=density*volume=.90g/ml*18m^3
= .90kg/m^3\ * 18m^3
Weight of oil= above massoil* 9.8N/kg
An oil tank is 3m long, 3 m wide and 2 m high, when it is full of coconut oil specific gravity of 0.90, find the downward force at the bottom of the tank.
3 answers
Given:
OIl
Sp G= 0.9
Dimension
3m x 3m and H= 2 m P=2mx 900kg/m^3 x 9.8m/sec^2
F= P x A P = 1800kg/m^3 x 9.8 m/sec^2
but: kg-m/sec^2 is Newton
P=Hdg P =17640 N/m^2
Area= Assume rectangular Tank P=17640 N/m^2 x9m^2
Area= 3x 3= 9^2 P=17640 x 9
F = 158760 N then divide by 9.8 = 16200 kg
OIl
Sp G= 0.9
Dimension
3m x 3m and H= 2 m P=2mx 900kg/m^3 x 9.8m/sec^2
F= P x A P = 1800kg/m^3 x 9.8 m/sec^2
but: kg-m/sec^2 is Newton
P=Hdg P =17640 N/m^2
Area= Assume rectangular Tank P=17640 N/m^2 x9m^2
Area= 3x 3= 9^2 P=17640 x 9
F = 158760 N then divide by 9.8 = 16200 kg
The downward force at the bottom of the tank when it is full of coconut oil with a specific gravity of 0.90 is 16200 kg or 158760 N.
2 answers