An office manager paid $675.95 for

Question

computer equipment. The office
manager bought one monitor for
$127.95 and hard drives for $68.50
each. Let x represent the number of
hard drives she purchased.
Write an equation that represents
this situation.
What are the operations involved in this
situation? How do you know?
How much would it cost the manager to
purchase 7 hard drives and 2 monitors?

Answer 1

To write the equation that represents the situation, we start with the total cost of the computer equipment of $675.95. The office manager bought one monitor for $127.95, and the hard drives are $68.50 each, where \( x \) is the number of hard drives. The equation will look like this:

\[ 127.95 + 68.50x = 675.95 \]

Operations Involved:

1. Addition: The cost of the monitor and the total cost of the hard drives is being added together.
2. Multiplication: The cost of a single hard drive ($68.50) is multiplied by the number of hard drives purchased (\( x \)) to get the total cost of all hard drives.

We know these operations are involved because we have to add the cost of the monitor and the total cost of the hard drives to equal the total amount spent, which is $675.95.

Cost for 7 Hard Drives and 2 Monitors

To find the total cost for purchasing 7 hard drives and 2 monitors, we calculate:

• Cost of 2 monitors: \( 2 \times 127.95 = 255.90 \)
• Cost of 7 hard drives: \( 7 \times 68.50 = 479.50 \)

Now, add these two amounts together:

\[ 255.90 + 479.50 = 735.40 \]

Therefore, the total cost for 7 hard drives and 2 monitors would be $735.40.