An office manager orders one calculator or one calendar for each of the office's 60 employees. Each calculator costs $12, and each calendar costs $10. The entire order totaled $700.

Question

Part A: Write the system of equations that models this scenario

Answer 1

Let x be the number of calculators ordered and y be the number of calendars ordered.
Then, we have:

x + y = 60 (since one calculator or calendar is ordered for each employee)
12x + 10y = 700 (the total cost of the order is $700, where each calculator costs $12 and each calendar costs $10)

Part B: Solve the system of equations using any method.

We can solve this system by substitution or elimination. Let's use elimination:

Multiplying the first equation by 10, we get:

10x + 10y = 600

Subtracting this equation from the second one, we get:

2x = 100

Solving for x, we get:

x = 50

Substituting x = 50 into the first equation, we get:

50 + y = 60

Solving for y, we get:

y = 10

Therefore, the office manager ordered 50 calculators and 10 calendars.