The sound traveled twice the depth of the water (down and back).
2*depth=1530m/s*3seconds
An oceanic depth-sounding vessel surveys the ocean bottom with ultrasound waves
that travel at 1530 m/s in seawater. The time delay of an echo to the ocean floor
below is 3 seconds. Find the depth of the water.
2 answers
From,
Speed=distance/time
Where,
S=1,530m/s, t=3s and d=?
=> d=s*t
D=1,530*3
D=4,590m
Speed=distance/time
Where,
S=1,530m/s, t=3s and d=?
=> d=s*t
D=1,530*3
D=4,590m
1 answer