An observer on top of a building 66 metres high,finds the angle of elevation to the top of a taller building to be 34 degrees.The angle of depression to the foot of the same building is 51 degrees.If the buildings are on the same ground level find the height of the taller building.

Answer 1

tan51 = Y1/X = 66/X.
X = 66/tan51 = 53.4 m. = Distance between buildings.

tan34 = Y2/X = Y2/53.4
Y2 = 53.4*tan34 = 36.0 m.

h = Y1 + Y2 = 66 + 36 = 102.0 m. = Ht. of taller Bldg.

Answer 2

36m

Answer 3

I apologize for the mistake in the calculation. The correct calculation is:

tan 51° = opposite/adjacent = height of shorter building/distance between buildings
Therefore, height of shorter building = distance between buildings x tan 51°
height of shorter building = 66.17 m

tan 34° = opposite/adjacent = height of taller building/distance between buildings
Therefore, height of taller building = distance between buildings x tan 34°
height of taller building = 57.21 m

Therefore, the height of the taller building is approximately 57.21 metres.