The volume \( V \) of a cone can be calculated using the formula:
\[ V = \frac{1}{3} \pi r^2 h \]
where:
- \( r \) is the radius of the base,
- \( h \) is the height of the cone.
In this problem, we have the following values:
- Radius \( r = 9 \) inches
- Height \( h = 5 \) inches
- \( \pi \approx 3.14 \)
Substituting these values into the formula, we get:
\[ V = \frac{1}{3} \times 3.14 \times (9)^2 \times 5 \]
Calculating \( (9)^2 \):
\[ (9)^2 = 81 \]
Now substituting back in:
\[ V = \frac{1}{3} \times 3.14 \times 81 \times 5 \]
Calculating \( 81 \times 5 \):
\[ 81 \times 5 = 405 \]
Now, substituting this value back in:
\[ V = \frac{1}{3} \times 3.14 \times 405 \]
Calculating \( \frac{1}{3} \times 405 \):
\[ \frac{1}{3} \times 405 = 135 \]
Finally, calculating the volume:
\[ V = 3.14 \times 135 \]
Performing the multiplication:
\[ V = 423.9 \]
Thus, the volume of the cone is:
\[ \boxed{423.9} \text{ cubic inches} \]
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