To calculate the volume of a cone, we use the formula:
\[ V = \frac{1}{3} \pi r^2 h \]
where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height.
Given that the base radius \( r \) is 9 inches and the perpendicular height \( h \) is 5 inches, we can substitute these values into the formula.
First, calculate \( r^2 \):
\[ r^2 = 9^2 = 81 \]
Now substitute \( r^2 \) and \( h \) into the volume formula:
\[ V = \frac{1}{3} \pi (81)(5) \]
Substituting \( \pi \) with 3.14:
\[ V = \frac{1}{3} \times 3.14 \times 81 \times 5 \]
Now calculate \( 81 \times 5 \):
\[ 81 \times 5 = 405 \]
So now the formula becomes:
\[ V = \frac{1}{3} \times 3.14 \times 405 \]
Calculate \( 3.14 \times 405 \):
\[ 3.14 \times 405 = 1277.7 \]
Now divide by 3:
\[ V = \frac{1277.7}{3} = 425.9 \]
Therefore, the volume of the cone is approximately:
\[ \boxed{425.9} \text{ cubic inches} \]