An object with a mass of 5 kg is thrown with an initial velocity of 6 m/s. If the object has an initial height of

10 meters above the ground, what is the magnitude of the initial gravitational potential energy of the
object? The acceleration due to gravity is 9.8 m/s2. (1 point)

400 joules

580 joules

90 joules

490 joules

1 answer

The gravitational potential energy (PE) of an object can be calculated using the formula:

\[ PE = mgh \]

where:

  • \( m \) is the mass of the object (in kg),
  • \( g \) is the acceleration due to gravity (in m/s²),
  • \( h \) is the height above the ground (in m).

Given:

  • \( m = 5 , \text{kg} \)
  • \( g = 9.8 , \text{m/s}² \)
  • \( h = 10 , \text{m} \)

Now, substituting the values into the formula:

\[ PE = 5 , \text{kg} \times 9.8 , \text{m/s}² \times 10 , \text{m} \]

\[ PE = 5 \times 9.8 \times 10 = 490 , \text{joules} \]

Therefore, the magnitude of the initial gravitational potential energy of the object is 490 joules.