The work done on the object is equal to the change in kinetic energy of the object. The kinetic energy of the object is given by KE = 0.5mv2, where m is the mass of the object and v is its velocity.
The initial kinetic energy of the object is 0.5 x 0.75 kg x (2.5 m/s)2 = 3.44 J.
The final kinetic energy of the object is 0 J, since it comes to rest after 3.0 s.
Therefore, the work done on the object is equal to the change in kinetic energy, which is 3.44 J.
An object with a mass of 0.75 kg is projected over a horizontal surface with a speed of 2.5 m/s. It then comes to rest after 3.0 s.
(b) How much work is done on the object?
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1 answer