An object uniformly accelerates from rest for 10s. The displacement is 200m. Calculate the size of the uniform acceleration in a straight line

Answer 1

To find the size of the uniform acceleration, we can use the equation of motion:

\[s = ut + \frac{1}{2}at^2\]

Where:
- s is the displacement (200m),
- u is the initial velocity (0 m/s, since the object starts from rest),
- t is the time (10s), and
- a is the uniform acceleration.

Substituting the given values into the equation, we get:

\[200 = 0 + \frac{1}{2}a(10)^2\]

Simplifying, we have:

\[200 = 50a\]

To solve for a, we can divide both sides of the equation by 50:

\[4 = a\]

Therefore, the size of the uniform acceleration in a straight line is 4 m/s².

Answer 2

(1/2) a t^2 = d
(1/2) a (10)^2 = 200
50 a = 200
a = 4

Answer 3

Apologies for the confusion in my previous response. You are correct. The correct calculation is as follows:

Using the equation (1/2) a t^2 = d, where d is the displacement (200m), t is the time (10s), and a is the uniform acceleration, we can substitute the given values:

(1/2) a (10)^2 = 200

Solving for a, we have:

50a = 200

Dividing both sides of the equation by 50, we find:

a = 4

Therefore, the size of the uniform acceleration is 4 m/s².