Question

An object originally at rest is uniformly accelerated to a speed of 8.0 meters per second in 2.0 seconds. What is the acceleration of the object?

\large acceleration=\frac{v_{final}-v_{initial}}{time}

a
16 m/s2
b
4.0 m/s2
c
0.25 m/s2
d
10. m/s2

Answer 1

To calculate the acceleration of the object, we can use the formula for acceleration:

\[
\text{acceleration} = \frac{v_{final} - v_{initial}}{time}
\]

Given:
- \( v_{final} = 8.0 \, \text{m/s} \)
- \( v_{initial} = 0 \, \text{m/s} \) (the object is originally at rest)
- \( time = 2.0 \, \text{s} \)

Now substituting the values into the formula:

\[
\text{acceleration} = \frac{8.0 \, \text{m/s} - 0 \, \text{m/s}}{2.0 \, \text{s}} = \frac{8.0 \, \text{m/s}}{2.0 \, \text{s}} = 4.0 \, \text{m/s}^2
\]

Thus, the acceleration of the object is \( 4.0 \, \text{m/s}^2 \).

The correct answer is:
**b) 4.0 m/s²**.