FF = ma = 6t^2i + 4tj
Since m=3,
a = 2t^2i + 4/3 t j
so,
v = 2/3 t^2 i + 2/3 t^2 j
an object of mass 3 kg is at rest. Now a force of vectorS = 6t2^i + 4tj^ is applied on the object then velocity of object at t = 3 sec. is?
3 answers
Oops --
v = 2/3 t^3 i + 2/3 t^2 j
v = 2/3 t^3 i + 2/3 t^2 j
Dun public school
1 answer