an object of mass 1kg falls a distance of 5m onto a horizontal surface and rebounds to a vertical height of 2m. calculate the change in momentum.

Answer 1

v^2 = mgh
on impact, v^2 = 5g, so p = √(5g)
on rebound, v^2 = 2g, so p = √(2g)

Answer 2

oops -- v^2 = 2gh