v down = sqrt (2 g h) = sqrt (2*9.8*5)
= 9.9 m/s
v up = sqrt (2 * 9.8*2)
= 6.26
change in momentu = m delta v = 1(9.9+6.26)
= 16.2 kg m/s
an object of mass 1kg falls a distance 5m on a horizontal surface and bounce to a vertical height of 2m.calculate the change in momentum
12 answers
I don't understand
Nice one đ
Joyce you recall
V² = U² + 2gh
But here u = 0
You now have
V = â2gh
So you use it to find the first and second velocity
V² = U² + 2gh
But here u = 0
You now have
V = â2gh
So you use it to find the first and second velocity
I didn't understand
Physical address
How did you get v down
It from the equation đ¤đ¤
I really understand. Thank you â¤ď¸â¤ď¸
I don't understand
I don't understand
I think Damon is correct
2 answers