An object of mass 0.50 kg on the end of a string is whirled round in a horizontal circle of radius 2.0m with a constant speed of 10m/s.Find its angular velocity and tension in the string( string is horizontal)answer should be 25.5 N

Answer 1

v = omega r
10 = omega(2)
omega = 5 radians/second

Ac = v^2/r = omega^2 r = 25*2 = 50 m/s^2

F = m a = .5 *50 = 25 N
(not 25.5)