an object of mass 0.5 kg is whirled at the end of string 0.8 m long if the string make three revolution in 1.2 sec find the tension of the string

Answer 1

tension = sum of centrietal force+gravity
notice these are vectors.

tensionvertical= mg down
tensionhorizonal= m w^2 * rad
= .5*(2PI/.4)^2 * .8

now, after calculating that, you add them as vectors

tension= sqrt ( (mg)^2+(horizonalabove)^2 )

Answer 2

35.6N

Answer 3

I want the nice explanation how the answer came

Answer 4

Good.......

Answer 5

A force of 50 N is applied tangentially to the rim of disk 20cm in radius and mass 30kg .find the angular acceleration of the disk?