An object of 3.0kg is projected into the air at a 55 degree angle. It hits the ground 3.4s later. What is it's change in momentum while it's in the air?

Answer 1

Y = Yo + g*Tr = 0
Yo - 9.8*(3.4/2) = 0
Yo = 16.66 m/s = Ver. component of initial velocity.

sin A = Yo/Vo
sin55 = 16.66/Vo
Vo = 16.66/sin55 = 20.34 m/s

Xo = Vo*Cos55 = 20.34*Cos55 = 11.67 m/s.

V = Xo+Yi = 11.67 + 0 = 11.67 m/s

Momentum change = M*V - M*Vo
M = 3.0 kg
V = 11.67 m/s
Vo = 20.34 m/s