An object moving in the positive x direction went from a velocity of 2.5 km/s to a velocity of 8.0 km/s in 6.2 seconds. What's the object's average acceleration?

Answer 1

v1 =2.5 km/s = 2500 m/s,
v2 = 8 km/s = 8000 m/s.
a =(v2-v1)/Δt = (8000-2500)/6.2 =
=887.1 m/s²