An object is traveling at a constant speed of 12.0 m/s when it slows to a stop. If it takes 10.0 m for the object to stop, what is the magnitude of its acceleration?

Answer 1

Using 2ad = Vf^2 - Vi^2

2(a)(10m)=(0m/s)^2-(12.0m/s)^2
20a=-144
a=-7.2 m/s^2