g = -980 cm/s^2
the object reaches its peak at 2 s
average velocity is 980 cm/s
... so peak height is 1960 cm
time up equals time down
An object is thrown vertically up ward from the ground with initial velocity 1960cm/s Neglecting air resistance, find the maximum height reached and the total time taken to return to the straight point ,/using first order differential equations/
1 answer