Hint: Set h to 46 and solve for t.When will the object reach the ground?
Incorrect
seconds
An object is thrown upward at a speed of 148 feet per second by a machine from a height of 20 feet off the ground. The height
h of the object after t seconds can be found using the equation
h=−16t2+148t+20
When will the height be 46 feet? (Note that there are TWO answers, one for moving up and one for moving down!)
2 answers
−16t^2+148t+20 = 46
-16t^2+148t-26 = 0
t = (37±√1265)/8
-16t^2+148t-26 = 0
t = (37±√1265)/8
1 answer