An object is thrown directly downwards from a height of 60m with an initial velocity of 11m/s. What will be its velocity on impact with the ground?

Answer 1

You would be solving:

-4.9t^2 - 11t + 60 = 0

sub into .....
velocity = -9.8t - 11

Answer 2

V^2 = Vo^2 + 2g*h = 11^2 + 19.6*60 = 1297.
V = 36.0 m/s.