You can start there, but there is a lot more to do
True weight (in air) = W
ethyl alcohol density = 790 kg/m^3
(You have to look that up)
Water density = 1000 kg/m^3
You have to solve for two unknowns, Weight W and Volume V. You have two equations to work with:
15.8 N = W - 790*9.8*V
13.0 N = W - 1000*9.8*V
NOW do the subtraction
2.8 N = 210*9.8 V
V = 1.36*10^-3 m^3
= 1.36 liters
W = 26.33 N
An object is solid throughout. When the object is completely submerged in ethyl alcohol, its apparent weight is 15.8 N. When completely submerged in water, its apparent weight is 13.0 N. What is the volume of the object?
Would I start by doing 15.8 - 13?
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