An object is released from rest on a planet that has no atmosphere. The object falls freely for 5.02 m in the first second. What is the magnitude of the acceleration due to gravity on the planet?

Answer in units of m/s

can someone help me please? i tried doing this
-5.02m =Xa
-5.02m =Vo*(t) + (1/2)*a(t^2)
-5.02m =(1/2)*a
-10.04m/s^2 = a

but its says that its wrong. can someone please help?

Similar Questions
  1. An object is released from rest on a planetthat has no atmosphere. The object falls freely for 5.03 m in the first second. What
    1. answers icon 1 answer
    1. answers icon 3 answers
  2. Question 6 (1 point)In the diagram below, two identical objects are released from rest at the starting position. Object 1 was
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions