An object is projected from a satellite orbiting 200 km above the surface of the earth. The object has a speed relative to the Earth of 2.85×104 m/s. What is its speed when it is very far from the earth?

Answer 1

find the GPE of the satellite at 200km . Add that to the KE at 200km. Then, assume it is all KE, find v.

GPE= GMe*m/d where d is distance from center of earth.

Answer 2

v=sqrt(2(-GM/d)+1/2(vi^2)) based on conservation of energy (gravitational potential energy and kinetic energy).