An object is placed 3cm in front of a diverging lens of focal length of 6cm. the heihgt of the object is 1.5 cm. calculate the image distance and height of the image

Answer 1

-1/6-1/3=-1/2
image distance=-2

hi/ho=-di/do
hi/1.5=-(-2)/3
hi=(2/3)x(3/2)
hi=1

Answer 2

i wantere being if two different conventions are there in applications. Since I saw two different systems being followed.