An object is located 51 millimeters from a diverging lens.The object has a height of 13 millimeters and the image height is 3.5 millimeters.How far in front of the lens is the image located?

Answer 1

|(image distance)/(object distance)| = (image size)/(object size)|

3.5/13 = (image distance)/51 mm

Image distance = 51*3.5/13 = 13.7 mm

You do not need to worry about minus signs and whether or not the lens is diverging to use this formula.

Answer 2

13.73

Answer 3

thanks

Answer 4

an object 5 millimeters high is loccated 15 millimeters in front of a plane mirror. How far from the mirror is the image located?