An object is launched at 19.6 meters per second from a 58.8 meter tall platform. The equation for the object's height s at time t seconds after launch is s(t) = -4.9t2+ 19.6t + 58.8, where s is in meters.

Question

a. When does the object strike the ground?
b. What was its maximum height?
c. How long will it take to reach its maximum height?

Answer 1

see this similar question

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Answer 2

iudk

Answer 3

a. 6 seconds