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An object is inside a room that has a constant temperature of 295 K. Via radiation, the object emits three times as much power as it absorbs from the room. What is the temperature (in kelvins) of the object? Assume that the temperature of the object remains constant.

I thought it would be 295/3 or 295 X 3 but I a not sure.

1 answer

radiated energy= constant*T^4
absorbed energy= constant*295^4

T^4=3*295^4

Temp= 295*sqrt (sqrt3)= ???

check my thinking, Hannah http://www.britannica.com/EBchecked/topic/564843/Stefan-Boltzmann-law
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