V=dh/dt= d(4.9t^2/dt=9.8t
but t can be found from 146.9=4.9t^2
an object is dropped from a tower. the distance in t seconds is given by d(t)=4.9t^2
if the height of the tower is 146.9m , how fast is an object moving when it hits the ground??
2 answers
Your equation should have been
dt) = - 4.9t^2
dt) = - 4.9t^2
2 answers