A motion question so think about the equations of motion:
v = u + at
v^2 = u^2 + 2aS
S = ut - (1/2)*a*t^2
u = initial vel
v = final vel
t = time
S = displacement
a = acceleration which in this case is gravity so g = 9.8 m/s^2
Don't forget that when throwing up gravity is against you so a = -g but when it's going downwards gravity is helping it so a = g then.
Write down what you know for the first part and see which equation you can use to find the time (t)
An object is being thrown upward at 50m How long does it take the object to reach maximum height? What is the maximum height of the object? How much time does it take for the audit to return to its original position? What is the velocity of the object when it hits the ground? How much time Total does it take for the advent to hit the ground?
2 answers
edit:
S = ut + (1/2)*a*t^2
Sorry about that. I was thinking of the upward throw and the - sneaked in.
S = ut + (1/2)*a*t^2
Sorry about that. I was thinking of the upward throw and the - sneaked in.