An object initially at rest experiences an acceleration of 1.4m/s2 for 8.0s and then travels at that constant velocity for another 6.0s . What is the object’s average velocity over the 14s interval?

Question

An object initially at rest experiences an acceleration of 1.4m/s2 for 8.0s and then travels at that constant velocity for another 6.0s .  What is the object’s average velocity over the 14s interval?

Damon · Answer

first stage v = a t = 1.4 * 8 = 11.2 m/s x = .5 a t^2 = .7 * 64 = 44.8 meters stage 2 Vi = 11.2 Xi = 44.8 a = 0 x = 44.8 + 11.2*6 = 112 went 112 meters in 14 seconds 112/14 = 8 meters/second average