An object initially at rest experiences an acceleration of 1.4 ­m/s² for 5.6 s then travels at that constant velocity for another 9.3 s. What is the magnitude of the object’s average velocity over the 14.9 s interval?

Answer 1

v = a t
v = 1.4 * 5.6
that is your constant velocity
x1 = (1/2) 1.4 (5.6)^2
that is where you are when you start your glide
x2 = x1 + v (9.3)
that is where you are at
t total = 5.6 + 9.3 = 14.9

avergae speed = x2/14.9