I will assume you want the equilibrant.
I will use vectors
R = 1200(cos51.3,sin51.3) + 1400(cos42,sin42)
= (750.291,936.516) + (1040.403, 936.828) carrying all decimals my calculator can hold
= (1790.694, 1873.299)
|R| = sqrt(1790.694^2 + 1873.299^2)
= 2591.493
tan(theta) = 1873.299/1790.694
theta = 46.29 degrees
so the resultant has direction 180 + 46.29 degrees= 226.29 degrees
and a magnitude of 2591.493 N
You might want to check my arithmetic by doing the question using the cosine law
An object has three forces acting on it 1200N at 51.3 degrees and 1400N at 42.0 degrees,what is the magnitude and direction of the third force?
4 answers
thank s
I did not understand
three force acting on an object figure 1.32.which is in equilibrium .determine force A