An object has a weight of 0.838 N. It is suspended from a scale, which reads 0.705 N when the piece is submerged in water. What are the volume and density of the piece of metal?

Answer 1

The buoyancy force is 0.838 - 0.705 = 0.133 N

Let D be the density and V be the volume

D*V*g = 0.838 newtons
(1000 kg/m^3)*V*g = 0.133 newtons
(That came from Archimedes principle)

D = 6300 kg/m^3 (or 6.3 g/cm^3)

V = 0.838/(6300 g) = 1.357*10^-5 m^3
= 13.57 cm^3