An object has a mass of 33.6 grams and a volume of 22.5 cm^3. It is placed in a beaker of seawater, which has a density of 1.03 g/cm^3. What kind of buoyancy will the object have?(1 point)

Question

Responses

Negatively buoyant
Negatively buoyant

Neutrally buoyant
Neutrally buoyant

Positively buoyant

Answer 1

To determine the buoyancy of the object, we need to compare its density to that of seawater.

First, we calculate the density of the object:

\[ \text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{33.6 , \text{g}}{22.5 , \text{cm}^3} \approx 1.49 , \text{g/cm}^3 \]

Now, we compare this density to the density of seawater, which is given as 1.03 g/cm³.

• If the density of the object is greater than the density of seawater, the object is negatively buoyant and will sink.
• If the density of the object is equal to the density of seawater, the object is neutrally buoyant and will neither sink nor float.
• If the density of the object is less than the density of seawater, the object is positively buoyant and will float.

Since the density of the object (1.49 g/cm³) is greater than the density of seawater (1.03 g/cm³), the object will be negatively buoyant.

The response is: Negatively buoyant.