An object has a constant acceleration of 40 ft/sec2, an initial velocity of -20 ft/sec, and an initial position of 10 ft

Answer 1

well, you know that

a = 40
v = ∫a dt = 40t + a
s = ∫v dt = 20t^2 + at + b

use the given conditions to find a and b.

Answer 2

s(t)= (20t sqrd -20t +10)

Use the formula
s(t)= (1/2)a tsqrd + V0t + S0