h=v_0+at^2
h=0+(-9.8)t^2
h=96.4(t)
.45h=96.4(1)
h=96.1/0.45
h=213.422ft
An object falls a distance h from rest. If it travels 0.45h in the last 1.00 s, find the time and the height of its fall.
2 answers
use this equation:
(0.45)h=(1/2)*g*(2t-1)
(0.45)h=(1/2)*g*(2t-1)