In order to calculate the greatest height from which the object can fall without breaking at a speed of 12m/s, we need to consider the kinetic energy of the object at the point of impact.
The kinetic energy of an object is given by the formula KE = 0.5*m*v^2, where m is the mass of the object and v is the velocity of the object.
Given that the speed of the object is 12m/s, the kinetic energy can be calculated as KE = 0.5*12^2 = 72 J.
At the highest point of the fall, the potential energy of the object is equal to the kinetic energy at impact.
The potential energy of an object at height h is given by the formula PE = m*g*h, where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the object.
Equating the potential energy at the highest point to the kinetic energy at impact, we get:
m*g*h = 72 J
We know that the object does not break when it hits the ground at the speed of 12m/s. This means that it will not be damaged when it reaches a height where it's potential energy is equal to its kinetic energy at the point of impact.
Therefore, the greatest height from which the object can fall without breaking is:
h = 72 / (m*g) = 7.3 m
So, the object can fall from a height of 7.3 meters without breaking when it hits the ground at a speed of 12m/s.
an object can hit the ground without breaking at speeds up to 12m/s what is the greatest height from which the object can fall
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