A. Mag. = 6.43/3.28 = 1.96
B. R = 2 f
Get the focal length f from the equation
1/do + 1/di = 1/f
do = object distance = 10.5 cm
di = image distance = 20.6 cm
An object 3.28 cm tall is placed 10.5 cm in front of a mirror, which creates an upright image rant is 6.43 cm in height.
A. What is the magnification of the image?
B. What is the radius of the curvature of the mirror?
2 answers
How did you get 20.6?