time to fall 1.13m
1.13=4.9t^2 solve for t, then use that t to find the initial horizontal velocity of the block/bullet
1.76=v'*t solve for v'
then conservation of momentum...
(m1+m2)v'=m1*v
solve for v.
An m1 = 8.40 g bullet is fired into a m2 = 2.17 kg block that is initially at rest at the edge of a frictionless table of height h = 1.13 m.
The bullet remains in the block, and after impact the block lands d = 1.76 m from the bottom of the table. Calculate the initial speed of the bullet.
1 answer