Let's consider the two cases separately:
Case 1: The isosceles triangle has two sides of length x cm each.
In this case, the third side must be 9 cm. The perimeter of the triangle is given by: x + x + 9 = 2x + 9. So we need to find the largest whole number value of x such that 2x + 9 < 24. Solving this inequality:
2x + 9 < 24
2x < 24 - 9
2x < 15
x < 7.5
Since x must be a whole number, the largest value it can have is 7.
Case 2: The isosceles triangle has one side of length 9 cm.
Let's call this side "a". So the other two sides must also be of length 9 cm each. In this case, the perimeter of the triangle is given by: 9 + 9 + 9 = 27. But we need the perimeter to be less than 24, so this case is not possible.
Therefore, the lowest value of x is 7 and the highest value of x is not possible (since it would make the perimeter greater than 24).
An isosceles triangle has sides of length x cm,x cm and 9 cm. It’s perimeter is less than 24 and x is a whole number. Find the lowest value of x and find the highest value of x.
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