If the base is 2x, then
12.5/x = tan 55°
The area is just 12.5x
An isosceles triangle has a height of 12.5 m (measured from the unequal side) and two equal angles that measure 55°. Determine the area of the triangle.
Split in half the triangle is a right triangle, so it's three angles are 90%, 55% and 70%.
I'm still not sure how to find the area.
2 answers
If you split it in half, the three angles are 90, 55, and 35 for one half. You basically find the base of one half of the triangle, multiply it by 2 (to find the base of the full triangle), multiply that by the height and divide it by 2:
tan55=12.5/x
xtan55/tan55=12.5/tan55
x=8.7526 (Rounded)
2x=2(8.7526)=17.5052 (Rounded)
A=bh/2
A=(17.5052)(12.5)/2
A=109.4m^2 (Rounded)
tan55=12.5/x
xtan55/tan55=12.5/tan55
x=8.7526 (Rounded)
2x=2(8.7526)=17.5052 (Rounded)
A=bh/2
A=(17.5052)(12.5)/2
A=109.4m^2 (Rounded)