An isolated segment of wire of length L=4.50 m carries a current of magnitude i=35.0 A at an angle theta=50.3 degrees with respect to a constant magnetic field with magnitude B= 6.70E-2 T. What is the magnitude of the magnetic force on the wire?
a) 2.66 N
b) 3.86
c) 5.60 N
d) 8.12 N
e) 11.8 N
What I did was:
F=ILxBsin(theta)
=(35.0A)(4.50m)*( 6.70E-2T * sin(50.3 degrees)
I got 8.12 N but I checked on the back of the book and it says that the answer is (e) but I don't know how to get that.