C = Q / 100...100 C = Q
capacitors add in parallel
the charge is the same (redistributed)
C + 10 = 100 C / 30
solve for C
An isolated capacitor of unknown capacitance has been charged to a potential difference of 100 V. When the charged capacitor is then connected in parallel to an un-
charged 10.0 μF capacitor, the potential difference across the combination is 30.0 V.
Calculate the unknown capacitance.
10.0µF=10*10^-6F. C=Q/V => c=(10*10^-6)/70= unknown capactitance?
Im guessing this is it?
1 answer
1 answer