An iron tyre of diameter 50cm at 15 degree celsius is to be shrunk on to a wheel of diameter 50.35cm.To what temperature must the tyre be heated so that it will slip over the wheel with a radial gap of 0.5mm?(co-efficient of linear expansion of iron 0.0000121 degree celsius)

Answer 1

R wheel = 50.35/2 + 0.005cm = 25.18 cm
Rtire= 25
so
d Rtire / R tire = 0.18/50 = coef * d Temp