An iron block has a length of 8 centimeters, a width of 5 centimeters, and a height of 4 centimeters. If the density of iron is 7,874 kg/m3 , which of the following correctly calculates the mass of the block?

1 answer

To calculate the mass of the iron block, you can use the formula:

\[ \text{Mass} = \text{Density} \times \text{Volume} \]

First, you need to calculate the volume of the block. The volume \( V \) of a rectangular block can be found using the formula:

\[ V = \text{Length} \times \text{Width} \times \text{Height} \]

Given the dimensions:

  • Length = 8 cm = 0.08 m
  • Width = 5 cm = 0.05 m
  • Height = 4 cm = 0.04 m

Now, calculate the volume:

\[ V = 0.08 , \text{m} \times 0.05 , \text{m} \times 0.04 , \text{m} = 0.00016 , \text{m}^3 \]

Next, use the density of iron, which is 7,874 kg/m³, to find the mass:

\[ \text{Mass} = \text{Density} \times \text{Volume} = 7,874 , \text{kg/m}^3 \times 0.00016 , \text{m}^3 \]

Now, perform this multiplication:

\[ \text{Mass} = 7,874 \times 0.00016 = 1.25984 , \text{kg} \]

Thus, the mass of the iron block is approximately 1.26 kg.