an investor invested a total of 1,100 in two mutual funds. One fund earned a 5% profit while the other earned a 2% profit. If the investor's total profit was 49.00 how much invested in each fund?
4 answers
sorry sandy idk how to do your problem. I did try though :( could you please take a look at mine right below yours though and see if you could tell me how to do it?
amount invested at 5% ---- x
amount invested at 2% ----- 1100 -x
.05x + .02(1100-x) = 49
.05x + 22 - .02x = 49
.03x = 27
x = 27/.03 = 900
invested at 5% = 900
invested at 2% = 200
check: 900+200=1100
.05(900) +.02(200) = 49
all is good!
amount invested at 2% ----- 1100 -x
.05x + .02(1100-x) = 49
.05x + 22 - .02x = 49
.03x = 27
x = 27/.03 = 900
invested at 5% = 900
invested at 2% = 200
check: 900+200=1100
.05(900) +.02(200) = 49
all is good!
x + y = 1,100
a + b = 49
(x+5%) + (y+2%) = 1,149
That's all I could take from the question. Now how you solve and get the answer is beyond me.
a + b = 49
(x+5%) + (y+2%) = 1,149
That's all I could take from the question. Now how you solve and get the answer is beyond me.
Ahh makes much more sense when Reiny did it. I remember learning this in algebra. I have a tendency to give everything its own variable, which makes the problem impossible to solve i guess.