suppose the radius of the original cone is r
then the base area of the original is πr^2
Now, the radius of your half-size cone is r/2
so the base area
= π(r/2)^2
= πr^2/4
= (1/4) πr^2
Thus the base area of the scaled down cone = 1/4 of the base area of the larger cone.
An inverted right cone, half filled with water. I've only the volume of the entire cone to go from.
So the volume of the cone = 1/3 the base area * height
I've been told by a friend that the base area of a half scale cone = 1/4 of the larger cones base area; with the height being half.
So... That would make the water equal to the total volume * (Ab * 1/4) * (H * 1/2)
Vc = 20cm^3
Vw = Vc * 1/4 * 1/2
Vw = 20cm^3/8
Vw = 2.5cm^3
What I don't understand is why the base area of the scaled down cone = 1/4 of the base area of the larger cone.
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