An insertion mutation occurs, leaving 31 nucleotides in a DNA sequence.
What is the maximum number of codons that could be produced by this sequence?
Choose 1 answer:
Choose 1 answer:
(Choice A) 10
A
10
(Choice B) 31
B
31
(Choice C) 11
C
11
(Choice D) 15
D
15
1 answer
The maximum number of codons that could be produced by a DNA sequence is determined by the number of nucleotides divided by 3. In this case, there are 31 nucleotides, so the maximum number of codons would be 31/3 = 10. Therefore, the correct answer is (Choice A) 10.
1 answer